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Section 8.8 The Ratio and Root Tests

We have just learned about one of the big and important tools that are used for testing convergence. The Limit Comparison Test is super useful for rational functions and things that act like \(p\)-Series, since these power functions and related function types behave so nicely, and are so friendly to work with, in the end behavior limit. The algebra typically works well, and we can analyze the limits pretty easily.
In this section, we’re going to try to draw a similar connection between our other family of common series, the Geometric Series, and series that act similarly. So for us to begin, we want to think about what it might mean for a series to have terms that act similarly to the terms of a geometric series.

Activity 8.8.1. Reminder about Geometric Series.

We are going to build some convergence tests that try to link some infinite series to the family of geometric series and show that even though a series is not geometric, it might act enough like one to be considered “eventually geometric-ish.”
But first, what does it mean for a series to be a geometric series?

(a)

Describe a defining characteristic of a geometric series. What makes it geometric?

(b)

Can you describe this characteristic in another way? For instance, if you described a geometric series using a characteristic about the Explicit Formula, can you describe the same characteristic in the context of the Recursion Relation instead? Or vice versa?
Hint 1.
What kinds of functions do we see in the formula for the terms of a geometric series?
Hint 2.
How do you describe how you might get from one term in a geometric series to the next one?

(c)

Write out a generalized and simplified form of the term \(a_k\) of a geometric series explicitly and recursively. In each case, solve for \(r\text{,}\) the ratio between terms.

Subsection Eventually Geometric-ish

We’re going to use these two guiding features of a geometric series to determine if a series is geometric-ish. That is, if a series is not actually a geometric series, do the terms act like terms from a geometric series in the limit? Is there some eventually (almost) constant ratio between consecutive terms? Is there one in the limit as \(k\to\infty\text{?}\) If the terms aren’t actually exponential functions of \(k\text{,}\) do they kind of act like that in the limit as \(k\to\infty\text{?}\) If so, shouldn’t they act like geometric series and converge with the same criteria?
So these tests are good and fine, but when do we use them? How do we know that they can be helpful? The key is to notice behavior in the terms of a series that look “kind of” geometric: we’re looking for \(k\) up in the exponent on things and we’re looking for repeated multiplication.

Activity 8.8.2. When Are These Tests Useful?

We’re going to look at a couple of small examples where we can rewrite some expressions into friendlier forms, and try to connect these rewriting strategies to the Ratio and Root Tests.
(a)
Rewrite the following expression into a friendlier form. Explain why this new form is friendlier.
\begin{equation*} \sqrt[k]{\frac{2^{k+1}}{7^{3k}}} \end{equation*}
(b)
Rewrite the following expression into a friendlier form. Explain why this new form is friendlier.
\begin{equation*} \sqrt[k]{\frac{(k+1)^{k}}{4^{2k+1}}} \end{equation*}
(c)
Rewrite the following expression into a friendlier form. Explain why this new form is friendlier.
\begin{equation*} \frac{(5^{k+2})(6^{k-3})}{(5^{k-1})(6^{k+1})} \end{equation*}
(d)
Rewrite the following expression into a friendlier form. Explain why this new form is friendlier.
\begin{equation*} \frac{103!}{99!} \end{equation*}
(e)
Rewrite the following expression into a friendlier form. Explain why this new form is friendlier.
\begin{equation*} \frac{(2k+4)!}{(2k+2)!} \end{equation*}
(f)
Why do you think the Ratio Test especially will be useful for series whose terms include factorials and exponentials?
Why do you think the Root Test will be useful for series whose terms include exponentials and functions raised to functions (of \(k\))?

Example 8.8.3.

For each infinite series, apply one of the Ratio or Root tests and interpret the conclusions of the test.
(a)
\(\displaystyle \sum_{k=0}^\infty \frac{2^k}{k!}\)
(b)
\(\displaystyle \sum_{k=0}^\infty \frac{k^2}{(k+1)^k}\)
(c)
\(\displaystyle \sum_{k=1}^\infty \frac{k\ln(k+1)}{e^{2k}}\)
(d)
\(\displaystyle \sum_{k=0}^\infty \frac{(-1)^k(k+2)}{(k!)(3^k)}\)
Hint.
This is an alternating series! We can show that this series converges using the Alternating Series Test, and so we really need to test for absolute convergence.
That works perfectly, though, since the Ratio and Root tests only test series with positive terms. So test the series:
\begin{equation*} \sum_{k=0}^\infty \frac{(k+2)}{(k!)(3^k)} \end{equation*}

Subsection Inconclusive Results

We’ve seen some of our series tests have some inconclusive results:
  • The Divergence Test is inconclusive when the limit of the terms is 0.
  • The Direct Comparison Test is inconclusive when the inequality is the “wrong” way around (like when the series we’re interested in has terms smaller than a diverging series, or has terms larger than a converging series). The Limit Comparison Test has the same issue (where the order of the inequality matters) when the limit we get is either 0 or \(\infty\text{.}\)
  • And now we find that the Ratio Test and Root Test are inconclusive when the limit we consider in the test is equal to 1.
So what does it really mean when the conclusion from the series convergence test is “we actually can’t tell if our series converges or now?”
In general, this means that we can find an example of a series that converges and an example of a series that diverges, where both give the same result of the test. We know, for example, that every converging series has terms where the limit of the terms is 0, but we have also see examples of series whose terms approach 0 in the limit that diverge. The first example we looked at that did this was the Harmonic Series.
For the Ratio and the Root Tests, specifically, though, we can glean some more information.
We introduced these convergence tests by thinking about whether or not a series could act like a Geometric Series in the long run (in the limit). And the tests do a great job of uncovering this eventually-geometric-ish behavior! So good, in fact, that (almost) any series that eventually acts kind of like a geometric series will be correctly classified as converging or diverging.
So what, then, does it mean when the Ratio or Root Test is inconclusive? Simply this: it means that the series we’re considering does not act like a geometric series.
Let’s consider the general \(p\)-Series, and apply the Ratio Test:
\begin{align*} r \amp = \lim_{k\to\infty} \frac{\left(\frac{1}{(k+1)^p}\right)}{\left(\frac{1}{k^p}\right)}\\ \amp = \lim_{k\to\infty} \frac{k^{p}}{(k+1)^p} \end{align*}
This limit is 1.
Note that this limit does not depend on the exponent, \(p\text{,}\) which means that the limit will be 1 when the \(p\)-series converges and also when the \(p\)-series diverges.
So, in a sense, when we get an inconclusive result from the Ratio or Root Tests, we are learning a lot about our series: it doesn’t act like a geometric series, and that’s likely because it does act like a \(p\)-series! We should try to approach this series again, this time looking for a suitable \(p\)-series to compare it to (whether directly or using the Limit Comparison Test).

Practice Problems Practice Problems

1.

For the Ratio Test, we note that if \(\displaystyle\lim_{k\to\infty} \left|\frac{a_{k+1}}{a_k}\right| \lt 1\text{,}\) then the series \(\sum a_k\) converges. Why is this? Explain some general intuition for why the Ratio Test guarantees convergence in this case.

2.

For the Root Test, we note that if \(\displaystyle\lim_{k\to\infty} \sqrt[k]{|a_k|}\lt 1\text{,}\) then the series \(\sum a_k\) converges. Why is this? Explain some general intuition for why the Root Test guarantees convergence in this case.

3.

Note that in both the Ratio and Root Tests above, that we use the absolute value of the terms. Is it possible, then, for the Ratio or Root Test to tell us that a series converges conditionally?

4.

Simplify each of the following expressions.
(c)
\(\sqrt[k]{\dfrac{2^k}{e^{k^2}}}\)
(f)
\(\dfrac{2^{k+1}(k)!}{2^k(k+1)!}\)

5.

For the following series, use the apply the Ratio or Root Test (whichever is more applicable) and interpret the results.
(a)
\(\displaystyle \sum_{k=1}^\infty \frac{(k+1)^2}{k!}\)
(b)
\(\displaystyle \sum_{k=1}^\infty \left(\frac{1}{k!}\right)^k\)
(c)
\(\displaystyle \sum_{k=2}^\infty \frac{k^2}{e^k}\)
(d)
\(\displaystyle \sum_{k=1}^\infty \frac{(-1)^k}{(3k)^{k}}\)
(e)
\(\displaystyle \sum_{k=1}^\infty \left(\frac{1}{\ln(k+1)}\right)^k\)
(f)
\(\displaystyle \sum_{k=1}^\infty \frac{k}{\pi^k}\)
(g)
\(\displaystyle \sum_{k=1}^\infty \left(\frac{k}{\pi}\right)^k\)
(h)
\(\displaystyle \sum_{k=1}^\infty \frac{(-1)^{k+1}k^k}{k!}\)
(i)
\(\displaystyle \sum_{k=1}^\infty \frac{k!}{(2k+1)!}\)

6.

For what values of \(p\) (with \(p \gt 0\)) will the following series converge?
\begin{equation*} \displaystyle \sum_{k=1}^\infty \frac{k^p}{k!} \end{equation*}

7.

For each of the following infinite series, use any methods we’ve learned about so far to determine whether the series converges or diverges. If it converges and you are able to tell what it converges to, say so and explain. If you cannot tell what it converges to, say so and explain. Clearly state the test or method you use or the type of series.
(a)
\(\displaystyle \sum_{k=2}^\infty \left( \frac{k^2-1}{(k^3-k+1)^4} \right)\)
(b)
\(\displaystyle \sum_{k=2}^\infty \left( \frac{1}{k\ln(k^4)} \right)\)
(c)
\(\displaystyle \sum_{k=0}^\infty \left( \frac{(-1)^{k} +2^k}{e^{2k}} \right)\)
(d)
\(\displaystyle \sum_{k=2}^\infty \left( \frac{1}{k^2-1}\right)\)
(e)
\(\displaystyle \sum_{k=2}^\infty \left( \frac{1}{k\sqrt{k^2-1}}\right)\)
(f)
\(\displaystyle\sum_{k=0}^\infty \left(\frac{4^k(k^2)}{k!}\right)\)
(g)
\(\displaystyle \sum_{k=2}^\infty \left( \frac{\ln(k)}{k+2}\right)\)